b, x-2+3x =10 =>2.(2x-1)=2.5 =>4x-2=10 =>4x=10+2 =>4x=12 =>x=12:4 => x=3 Vậy x=3. Mk làm đại đúng thì đúng sai thì sai nha nhg mk đoán thì đúng
a)3x−1+5.3x−1=162
⇔6.3x−1=162
⇔3x−1=27
⇔3x−1=33
⇔x−1=3
⇔x=4
a) \(\left(1+5\right).3^{x-1}=162\)
\(6.3^{x-1}\)=162
\(3^{x-1}=162:6\)
\(3^{x-1}=27\)
\(x-1=27:3\)
x - 1 = 9
x = 9 + 1
x = 10
Bạn ơi sửa cho mik chỗ 3x-1= 33
\(\Rightarrow\)x - 1 = 3
x = 3 + 1
x = 4
a) \(3^{x-1}\) \(+\) \(5.3^{x-1}\) = \(162\)
\(1.3^{x-1}\) \(+\) \(5.3^{x-1}\)= \(162\)
\(6.3^{x-1}\) = \(162\)
\(3^{x-1}\) = \(162\)\(:\)\(6\)
\(3^{x-1}\) = \(27\)
\(3^{x-1}\) = \(3^3\)
\(x-1\) = \(3\)
\(x\) = \(2\)
- Hok T -
a, 3x-1 + 5.3x-1 = 162
3x-1. ( 1 + 5) = 162
3x-1 . 6 = 162
3x-1 = 162 : 6
3x-1 = 27
3x-1 = 33
=> x-1 = 3
x = 3+1
x = 4
b) \(x-2+3x\) = \(10\)
\(x-2+x\) = \(\frac{10}{3}\)
\(\left(x+x\right)-2\)= \(\frac{10}{3}\)
\(x.2\) = \(\frac{16}{3}\)
\(x\) = \(\frac{16}{6}\)
x-2 +3x =10
4x -2 = 10
4x = 10 +2
4x = 12
x = 12:4
x = 3
b: Ta có: x+3x−2=10x+3x−2=10
⇔4x=12⇔4x=12
hay x=3
3x−1+5.3x−1=162
⇔6.3x−1=162
⇔3x−1=27
⇔3x−1=33
⇔x−1=3
⇔x=4
mk làm cả 2 câu r
k cho mk nhé
hok tốt
