A = 3+32+33+.....+3100
3A = 32+33+34+....+3101
2A = 3A - A = 3101-3 < 3101
=> A = \(\frac{3^{101}-3}{2}
A = 3 + 32 + 33 + 34 +.............3100
3A =32 + 33 + 34 +.............3101
3A - A = (3 + 32 + 33 + 34 +.............3100) - (32 + 33 + 34 +.............3101)
2A = 3101 - 3
\(A=\frac{3^{101}-3}{2}\)
B = 3101
Ta có A < B