Question

a/\(^{3+2^{x-1}=24-\left[4^2-\left(2^2-1\right)\right]}\)

b/(x+1)+(x+2)+(x+3)+....+(x+100)=205550

c/Ix-5I=18+2x(-8)

d/\(\left(3x-2^4\right).7^5=2.7^6.\frac{1}{2009^0}\)

Answer 1

b/100x+(1+2+3+...+100)=205550

100x+5050=205550

100x=205550-5050

100x=200500

x=200500/100

x=2005

Answer 2

d/(3x-2⁴).7⁵=2.7⁶.1/2009⁰

(3x-2⁴).7⁵=2.7⁶.1

(3x-2⁴)=2.7⁶:7⁵

(3x-2⁴)=2.7

3x-16=14

3x=14+16

3x=30

x=30/10=3

Answer 3

b) ( \(x\)+ 1 ) + ( \(x\)+ 2 ) + ( \(x\)+ 3 ) + ... + ( \(x\)+ 100 ) = 205550

\(x\)x 100 + ( 1 + 2 + 3 + ... + 100 ) = 205550

\(x\)x 100 + 5050 = 205550

 \(x\)x 100 = 205550 - 5050 

\(x\)x 100 = 200500

\(x\)= 200500 : 100

\(x\)= 2005

Answer 4

a)3+2^x-1=24-[4²-(2²-1)]

3+2^x-1=24 - [16-(4-1)]

3+2^x-1=24 - [16-3]

3+2^x-1=24 -13

3+2^x-1=11

    2^x-1=11-3

    2^x-1=8

    2^x-1=2³

     x-1=3

    x=3+1

    x=4