Question

A=288-18x13+567:17

B=\(\frac{1}{7}\)x\(3\frac{1}{11}\)\(-\frac{9}{11}\)\(+\frac{1}{7}\)

Answer 1

A = 288 - 18x13 +567:17

A = 288 - 234 + \(\frac{567}{17}\)

A = \(\frac{1485}{17}\)

 

Answer 2

\(A=288-18\cdot13+567:17\)

\(A=288-234+567:17\)

\(A=288-234+\frac{567}{17}\) 

\(A=54+\frac{567}{17}\)

\(A=87\frac{6}{17}=\frac{1485}{17}\)

\(B=\frac{1}{7}\cdot3\frac{1}{11}-\frac{9}{11}+\frac{1}{7}\)

\(B=\frac{1}{7}\cdot\frac{34}{11}-\frac{9}{11}+\frac{1}{7}\)

\(B=\frac{34}{77}-\frac{9}{11}+\frac{1}{7}\)

\(B=\frac{-29}{77}+\frac{1}{7}\)

\(B=\frac{-18}{77}\)

 

Answer 3

 A = 288 - 18 x 13 + 567 : 17

A = 288 - 234 + 567 : 17

A = 288 - 234 + \(\frac{567}{17}\)

A = 54 + \(\frac{567}{17}\)

A = 87\(\frac{6}{17}\)= \(\frac{1485}{17}\)

B = \(\frac{1}{7}\)x 3\(\frac{1}{11}\) - \(\frac{9}{11}\) + \(\frac{1}{7}\)

B = \(\frac{1}{7}\)x 3\(\frac{1}{11}\)-\(\frac{9}{11}\) + \(\frac{1}{7}\)

B = \(\frac{34}{77}\) - \(\frac{9}{11}\) + \(\frac{1}{7}\) 

B = \(\frac{-29}{77}\) + \(\frac{1}{7}\) 

B = \(\frac{-18}{77}\)