Question

A,248x(36+62)-148x(62+36)

B,107x195+107x175-107x150

C,(2020x99+2020)-(2019x101-2019)

Giúp mik ạ

Answer 1

`@` `\text {Ans}`

`\downarrow`

`A,`

`248 \times (36 + 62) - 148 \times (62 + 36)`

`= (36+62) \times (248 - 148)`

`= 98 \times 100`

`= 9800`

`B,`

`107 \times 195 + 107 \times 175 - 107 \times 150`

`= 107 \times (195 + 175 - 150)`

`= 107 \times 220`

`= 23540`

`C,`

`(2020 \times 99 + 2020) - (2019 \times 101 - 2019)`

`= 2020 \times (99+1) - 2019 \times (101-1)`

`= 2020 \times 100 - 2019 \times 100`

`= 100 \times (2020 - 2019)`

`= 100 \times 1`

`= 100`

Answer 2

A. 248x(36+62)-148x(62+36)

=(36+62)x(248-148)

=98x100

=9800

B.107x195+107x175-107x150

=107x(195+175-150)

=107x220

=23540

C.(2020x99+2020)-(2019x101-2019)

=(2020x(99+1))-(2019x(101-1))

=(2020x100)-(2019x100)

=202000-201900

=100

Answer 3

(145*99+145)-(143*101-143)

giup minh voi