đủ rồi nhìn thế ai chẳng biết tìm a,b
đề như thế này phải ko: \(\frac{a}{2}+\frac{b}{3}=\frac{a+b}{2+3}\)
\(\Leftrightarrow\frac{2b+3a}{6}=\frac{b+a}{5}\)
\(\Rightarrow\frac{2b+3a}{6}-\frac{b+a}{5}=0\)
\(\Rightarrow\frac{4b+9a}{30}=0\)
\(\Rightarrow4b+9a=0\)
\(\Leftrightarrow\)\(\frac{2b+3a}{6}=\frac{b+a}{5}\)
\(\Rightarrow\)\(\frac{2b+3a}{6}-\frac{b+a}{5}=0\)
\(\Rightarrow\frac{4b+9a}{30}=0\)
\(\Rightarrow4b+9a=0\)
a/2+b/3=a+b/2+3
=>3a+2b/6=a+b/5
=>2(a+b)+a/6=a+b/5
=>2(a+b)/6+a/6=a+b/5
=>a+b/3+a/6=a+b/5
=>a+b/3-a+b/5=a/6
=>2(a+b)/15=a/6
=>2.6.(a+b)=a.15
=>12.(a+b)=a.15
=>12.a+12.b=a.15
=>12.b=3.a
=>4.b=a
Lai co:a/2+b/3=(a+b)/2+3
=>(3.a+2.b)/6=(a+b)/5
=>3.a+2.b/6-(a+b)/5=0
=>(4.b+9.a)/30=0
=>4.b+9.a=0 maf 4.b=a
Khi do:a+9.a=0
=>10.a=0
=>a=0
=>4.b=0=>b=0
Vay a=0;b=0