Question

  \(A=1+\dfrac{1}{2}+\left(\dfrac{1}{2}\right)^2+\left(\dfrac{1}{2}\right)^3+.......+\left(\dfrac{1}{2}\right)^{2022}\)      Giups mik với mik cần gấp ạ

Answer 1

\(\dfrac{1}{2}A=\dfrac{1}{2}+\left(\dfrac{1}{2}\right)^2+\left(\dfrac{1}{2}\right)^3+\left(\dfrac{1}{2}\right)^4+...+\left(\dfrac{1}{2}\right)^{2023}\)

\(A-\dfrac{1}{2}A=\left(\dfrac{1}{2}\right)^{2023}-1\)

\(\dfrac{1}{2}A=\left(\dfrac{1}{2}\right)^{2023}-1\)

\(A=\dfrac{1}{2^{2022}}-2\)

Answer 2

A−12A=(12)2023−1A−12A=(12)2023−1

A=122022−2