\(\dfrac{15}{1}\) + \(\dfrac{9}{3}\) = \(\dfrac{45}{3}\) + \(\dfrac{9}{3}\) =\(\dfrac{54}{3}\)
a)15+9/3 = 45/3 + 9/3 = 54/3 = 18
b)4/9-5/7= 28/63 - 45/63 = -17/63
\(a,15+\dfrac{9}{3}=\dfrac{45}{3}+\dfrac{9}{3}=\dfrac{54}{3}=18\)
\(b,\dfrac{4}{9}-\dfrac{5}{7}=\dfrac{28}{63}-\dfrac{45}{63}=-\dfrac{17}{63}\)
a) 15+\(\dfrac{9}{3}=15+3=18\)
b)\(\dfrac{4}{9}-\dfrac{5}{7}=\dfrac{28}{63}-\dfrac{45}{63}=\dfrac{-17}{63}\)