Question

A=1+3+3^2+3^3+......+3^99+3^100

đề bài là rút gọn biểu thức nha

Answer 1

\(A=1+3+3^2+3^3+...+3^{99}+3^{100}\\ \Rightarrow3A=3+3^2+3^3+...+3^{100}+3^{101}\\ \Rightarrow3A-A=3^{101}-1\\ \Rightarrow2A=3^{101}-1\\ \Rightarrow A=\left(3^{101}-1\right).\dfrac{1}{2}\\ \Rightarrow\dfrac{3^{101}}{2}-\dfrac{1}{2}.\)

Answer 2

\(A=1+3+3^2+3^3+...+3^{99}+3^{100}\)

Ta có: \(3A=3+3^2+3^3+...+3^{99}+3^{100}\)

Khi đó: \(3A-A=3+3^2+3^3+...+3^{99}+3^{100}+3^{101}-\left(1+3+3^2+3^3+...+3^{99}+3^{100}\right)\)

\(=3^{101}-1\)

\(\Leftrightarrow2A=3^{101}-1\)

Vậy \(A=\left(3^{101}-1\right):2\)

Answer 3

em cảm ơn mọi nguoif ạ