Lời giải:
Xét tử số:
$101+100+99+98+...+3+2+1=(101+1).101:2=5151$
Xét mẫu số:
$101-100+99-98+...+3-2+1$
$=(101-100)+(99-98)+...+(3-2)+1=\underbrace{1+1+....+1}_{50} +1=1.50+1=51$
Vậy $A=\frac{5151}{51}=101$
Lời giải:
Xét tử số:
$101+100+99+98+...+3+2+1=(101+1).101:2=5151$
Xét mẫu số:
$101-100+99-98+...+3-2+1$
$=(101-100)+(99-98)+...+(3-2)+1=\underbrace{1+1+....+1}_{50} +1=1.50+1=51$
Vậy $A=\frac{5151}{51}=101$
101+100+99+98+...+3+2+1/101-100+99-98+...+3-2+1
B=(101+100+99+98+.....+3+2+1) / (101-100+99-98+.......+3-2+1)
B=(101+100+99+98+.....+3+2+1) / (101-100+99-98+.......+3-2+1)
A=101+100+98+97+...+3+2+1/101-100+99-98+...+3-2+1
A] 101-100+99-98+.......+3-2+1
B] 101+100+99+98+.......+3+2+1
101 +100+99+98+.........+3+2+1
101-100+99+98+.....+3-2+1
101+100+99+98+...+3+2+1
101-100+99-98+...+3-2+1
A=101+100+99+98+....+3+2+1/101-100+99-98+...+3-2+1
B=423134.846267-423133/423133.846267+423134
Rút gọn S=101+100+99+98+...+3+2+1 :101-100+99-98+...+3-2+1