\(A=\left(1+3+5+......+19\right)-\left(2+4+6+..........+20\right)\)
\(=\left(\frac{\left(19+1\right).10}{2}\right)-\left(\frac{\left(20+2\right).10}{2}\right)\)
\(=100-110\)
\(=-10\)
vậy A ko chia hết cho cả 2,3,5
\(Ư\left(A\right)=Ư\left(-10\right)=\left\{-10;-5;-2;-1;1;2;5;10\right\}\)