Question

a) x+(x+1)(x+2)+....+(x+2010)=2029099

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Answer 1

a) x+(x+1)(x+2)+....+(x+2010)=2029099

( x + x + x + ... + x ) + ( 1 + 2 + .... + 2010 ) = 2029099

2011x + 2021055 = 2029099

2011x = 2029099 - 2021055

2011x = 8044

x = 8044 : 2011

x = 4

vậy x = 4

Answer 2

x + ( x + 1 ) + ( x + 2 ) + .... + ( x + 2010 ) = 2029099

 x . 2011 + ( 1 + 2 + ... + 2010 ) = 2029099

x . 2011 + 2021055 = 2029099

x . 2011 = 2029099 - 2021055

x . 2011 = 8044

        x = 8044 : 2011

         x = 4

Answer 3

Xx(1+2+3+4.....+2010)=2029099

Có 2010 so

(2010+1)x2010:2=2021055

Co 2011 so X

2021255:2011==1005

X=1005