Question

a , x.(x +2/3) = 0

b,x.x+2x= 0

Answer 1

2k7 nek

Answer 2

a) \(x\left(x+\frac{2}{3}\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x+\frac{2}{3}=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=0\\x=-\frac{2}{3}\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x=-\frac{2}{3}\end{cases}}\)

b) \(x.x+2x=0\)

\(\Leftrightarrow x^2+2x=0\)

\(\Leftrightarrow x\left(x+2\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x+2=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=0\\x=-2\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x=-2\end{cases}}\)

Answer 3

a) x . ( x + 2/3 ) = 0

x = 0

hoặc x + 2/3 = 0 => x = -2/3

Vậy x = 0 hoặc x = -2/3

b) x . x + 2x = 0

x . ( x + 2 ) = 0

x = 0

hoặc x + 2 = 0 => x = -2

Vậy x = 0 hoặc x = -2

=))

Answer 4

a , x . ( x + 2 / 3 ) = 0

=> x = 0 ; x + 2 / 3 = 0

=> x = 0 ; x = - 2 / 3 

Answer 5

a,\(x\left(x+\frac{2}{3}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x+\frac{2}{3}=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x=-\frac{2}{3}\end{cases}}\)

b,\(x.x+2x=0\)

\(\Rightarrow x\left(x+2\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x+2=0\end{cases}\Rightarrow}\orbr{\begin{cases}x=0\\x=-2\end{cases}}\)

Answer 6

\(a;x\left(x+\frac{2}{3}\right)=0\)

\(\Leftrightarrow x^2+\frac{2}{3}x=0\)

\(\Leftrightarrow x^2=-\frac{2}{3}x\)

Mà x²>0 với mọi x

nên x<0

\(\Rightarrow x^2=-\frac{2}{3}x\Leftrightarrow x=-\frac{2}{3}\)

Answer 7

a) x^2 + 2/3.x=0

mà x^2 >0 với mọi x =>

x^2=2/3.x=0

=>x=0

b)x.(x+2)=0

=> x=0 hoặc x+2=0

=> x=0 hoặc x = -2

Answer 8

cho mình 1 k

Answer 9

b , x .x + 2x = 0

=>  x . ( x + 2 ) = 0

=>  x = 0 ; x + 2 = 0 

=>  x = 0 ; x  = -2

Answer 10

\(a,x\times\left(x+\frac{2}{3}\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x+\frac{2}{3}=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x=-\frac{2}{3}\end{cases}}\)

\(b,x\times x+2x=0\)

\(\Rightarrow x\times\left(x+2\right)=0\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x+2=0\end{cases}}\)

\(\Rightarrow\orbr{\begin{cases}x=0\\x=-2\end{cases}}\)

~Study well~

#Thạc_Trân

Answer 11

\(a.\)\(x.\left(x+\frac{2}{3}\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x+\frac{2}{3}=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=0-\frac{2}{3}\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=-\frac{2}{3}\end{cases}}\)

\(b.\)\(x.x+2x=0\)

\(\Leftrightarrow x.\left(x+2\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x+2=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=0-2\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=-2\end{cases}}\)

~ Rất vui vì giúp đc bn ~