Question

a) x+\(\dfrac{4}{9}\)= \(\dfrac{2}{3}\)_{x\(\dfrac{6}{7}\)}

Answer 1

\(x+\dfrac{4}{9}=\dfrac{4}{7}\\ x=\dfrac{4}{7}-\dfrac{4}{9}\\ x=\dfrac{8}{63}\)

Answer 2

Ta có :

x + \(\dfrac{4}{9}\) = \(\dfrac{2}{3}\) x \(\dfrac{6}{7}\)

x + \(\dfrac{4}{9}\) = \(\dfrac{4}{7}\)

x = \(\dfrac{4}{7}\) - \(\dfrac{4}{9}\)

x = \(\dfrac{8}{63}\)

Answer 3

\(x+\dfrac{4}{9}=\dfrac{2}{3}.\dfrac{6}{7}\)

⇔\(x+\dfrac{4}{9}=\dfrac{4}{7}\)

⇔\(x=\dfrac{8}{63}\)

Answer 4

x + 4/9 = 2/3 x 6/7

x = 4/7 - 4/9

x = 8/63