Question

A = x^3 + 3x^2 + 3x    tai x = 29

Answer 1

Thay \(x=29;\)ta có :

\(A=29^3+3.29^2+3.29\)

\(=29.\left(29^2+3.29+3\right)\)

\(=29.\left(841+87+3\right)\)

\(=29.931\)

\(=26999\)

Vậy ....

Answer 2

thay x=29 vào A

\(A=29^3+3.29^2+3.29\)

\(=29^3+3\left(29^2.29\right)\)

\(=29^3.4\)