Question

a, (x^2-2x+1)-4=0

b,x^2-x=-2+2

Answer 1

`a, (x-1)^2 - 4 = 0`

`<=> (x-3)(x+1) = 0`

`=> x - 3 = 0`

      `x + 1 = 0`

`=> x = 3`

     `x = -1`

b, `x^2 - x = - 2 + 2`

`<=> x^2 - x = 0`

`<=> x(x-1) = 0`

`=> x = 0`

     `x - 1 = 0`

`=> x = 0`

     `x = 1`.

Answer 2

\(a,\left(x-1\right)^2-2^2=0\\ \Leftrightarrow\left(x-1-2\right)\left(x-1+2\right)=0\\ \Leftrightarrow\left(x-3\right)\left(x+1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x-3=0\\x+1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}x=3\\x=-1\end{matrix}\right.\) 
\(b,x^2-x=0\\ \Leftrightarrow x\left(x-1\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x-1=0\Leftrightarrow x=1\\x=0\end{matrix}\right.\)

Answer 3

\(a, (x^2-2x+1)-4=0\)

\(=> (x-1)^2-2^2=0\)

\(=>(x-1-2)(x-1+2)\)

\(=> (x-3)(x+1)=0\)

\(=>x-3=0<=>x=3\)

\(=>x+1=0=>x=-1\)

\(------------\)

b đề có thiếu 

b,x^2-x=-2x+2