Lê Hoàng Khả Nhi
a, x.0 = 0
=> x = 0
b, 23( x -4) = 23
=> x -4 = 23/23
=> x -4 = 1
=> x = 1 + 4
=> x = 5
c, 12x + 40 = 76
=> 12x = 76 -40
=> 12x = 36
=> x = 36/12
=> x = 3
a) \(x.0=0\)
\(=>x\)có vô số nghiệm
b) \(23\left(x-4\right)=23\)
\(23x-92=23\)
\(23x=115\)
\(x=5\)
vậy \(x=5\)
c) \(12x+40=76\)
\(12x=36\)
\(x=3\)
vậy \(x=3\)
a) x.0=0
=> x \(\varepsilon\)N
b) 23(x-4)=23
x-4 = 23-23
x-4 =0
x = 0+4
x = 4
c) 12x +40=76
12x = 76-40
12x = 36
x = 36:12
x = 3
Ung ho mk nha cac bn!
x .0 =0
\(\Leftrightarrow x\)khác 0 thì thoả mãn
b, \(23\left(x-4\right)=23\)
\(\left(x-4\right)=23:23\)
\(\left(x-4\right)=1\)
\(x=1+4\)
\(x=5\)
c, 12x +40= 76
\(12x=76-40\)
\(12x=36\)
\(x=36:12\)
\(x=3\)
a) x.0=0 <=> x \(\in\) Z
b) 23(x-4)=23
x-4 = 23:23
x-4 = 1
x = 1+4
x = 5
c) 12x+40=76
12x = 76-40
12x = 36
x = 36:12
x = 3
