Các câu hỏi tương tự
1) \(3^x+3^{x+2}=810\)
2) \(\left(\dfrac{2}{3}x-1\right).\left(0,4x+5\right)=0\)
Tìm x biết:
\(\left|x+1\right|+\left|x+2\right|+\left|x+3\right|+\left|x+4\right|=5x-1\)-1
\(\left|x+1,1\right|+\left|x+1,2\right|+\left|x+1,3\right|+\left|x+1,4\right|=5x\)
\(\left|x+1\right|-\left|3x+2\right|=x+2\)
Bài 1:
a) |2x - 3| - \(\dfrac{1}{3}\)= 0
b) \(\dfrac{5}{6}-\left|x+\dfrac{1}{4}\right|=\dfrac{1}{4}\)
c) \(\left|2x-1\right|-\left|x+\dfrac{1}{3}\right|=0\)
d) \(3x-\left|x+15\right|=\dfrac{5}{4}\)
Bài 2:
a) A= 1,3 + 2,5
b) B= -4,3 - 13,7 + (-5,7) - 6,3
c) C= 25.(-5).(-0,4).(-0,2)
d) D=|11,4 - 3.4| + |12,4 - 15,5|
Bài 2 : Rút gọn biểu thức sau :
a ) \(A=\left|x+1,3\right|-\left|x-2,5\right|.\)khi \(x< -1,3\)
b ) \(D=\left|x+3\frac{1}{2}\right|+\left|x\right|-3\frac{1}{2}\)với \(x>0\)
c ) \(A=\left|x-\frac{1}{7}\right|-\left|x+\frac{3}{5}\right|+\frac{4}{5}\)khi \(-\frac{3}{5}< x< \frac{1}{7}\)
Bài 1:
a) \(\left(x-1,3\right)^2=9\)
b) \(2^{4-x}=32\)
c) \(\left(x+1,5\right)^2+\left(y-2,5\right)^{10}=0\)
\(\left(\dfrac{2}{3}x-1\right).\left(0,4x+5\right)=0\)
Mình cần gấp bài này !!!
1/Tìm x, biết :
a/ \(\frac{7}{\left(x+3\right)\left(x+10\right)}+\frac{11}{\left(x+10\right)\left(x+21\right)}+\frac{13}{\left(x+21\right)\left(x+34\right)}+\frac{x}{\left(x+3\right)\left(x+34\right)}\)
b/ \(\frac{3}{\left(x-4\right)\left(x-7\right)}+\frac{6}{\left(x-7\right)\left(x-13\right)}+\frac{15}{\left(x-13\right)\left(x-28\right)}-\frac{1}{x-28}=\frac{-1}{20}\)
Tìm x biếta)left|2x-3right|-xleft|2-xright|b)left|x+3right|+left|x+1right|3xc)2005left|x-4right|+left|x-10right|+left|x+101right|+left|x+990right|+left|x+1000right|d)left|x+frac{1}{2}right|+left|x+frac{1}{6}right|+left|x+frac{1}{20}right|+..+left|x+frac{1}{110}right|11x
Đọc tiếp
Tìm x biết
a)\(\left|2x-3\right|-x=\)\(\left|2-x\right|\)
b)\(\left|x+3\right|+\left|x+1\right|=\)\(3x\)
c)\(2005=\left|x-4\right|+\left|x-10\right|+\left|x+101\right|+\left|x+990\right|+\left|x+1000\right|\)
d)\(\left|x+\frac{1}{2}\right|+\left|x+\frac{1}{6}\right|+\left|x+\frac{1}{20}\right|+..+\left|x+\frac{1}{110}\right|=11x\)
chứng minh rằng các biểu thức sau không phụ thuộc vào x:
a. \(A=\left(3x+7\right)\left(2x+3\right)-\left(3x-5\right)\left(2x+11\right)\)
b. \(B=\left(x^2-2\right)\left(x^2+x-1\right)-x\left(x^3+x^2-3x-2\right)\)
c. \(C=x\left(x^3+x^2-3x-2\right)-\left(x^2-2\right)\left(x^2+x-1\right)\)