Các câu hỏi tương tự
giải hệ pt :
\(\hept{\begin{cases}3x^2+6xy+9y^2+\left(x+2y\right)^2\sqrt{x+2y}-3\left(x+2y\right)\sqrt{x+2y}-4\left(x+2y\right)+4\sqrt{x+2y}=0\\\left(\frac{\sqrt[3]{x^2-y^2}}{\sqrt[4]{x}}+\sqrt[4]{\frac{x}{y}}\right)^{2017}+\left(\sqrt[3]{\frac{x}{y}}-\sqrt[4]{\frac{y}{x}}\right)^{2018}=1\end{cases}}\)
Pleft(frac{sqrt{x}-2}{x-1}-frac{sqrt{x}+2}{x+2sqrt{x}+1}right)frac{left(1-xright)^2}{2}Pleft(frac{sqrt{x}-2}{left(sqrt{x}-1right)left(sqrt{x}+1right)}-frac{sqrt{x}+2}{left(sqrt{x}+1right)^2}right)frac{left(1-xright)^2}{2}Pleft(frac{left(sqrt{x}-2right)left(sqrt{x}+1right)-left(sqrt{x}+2right)left(sqrt{x}-1right)}{left(x-1right)left(sqrt{x}+1right)}right)frac{left(x-1right)^2}{2}Pleft(frac{left(x-sqrt{x}-2right)-left(x+sqrt{x}-2right)}{left(x-1right)left(sqrt{x}+1right)}right)frac{left(x-1right)^...
Đọc tiếp
\(P=\left(\frac{\sqrt{x}-2}{x-1}-\frac{\sqrt{x}+2}{x+2\sqrt{x}+1}\right)\frac{\left(1-x\right)^2}{2}\)
\(P=\left(\frac{\sqrt{x}-2}{\left(\sqrt{x}-1\right)\left(\sqrt{x}+1\right)}-\frac{\sqrt{x}+2}{\left(\sqrt{x}+1\right)^2}\right)\frac{\left(1-x\right)^2}{2}\)
\(P=\left(\frac{\left(\sqrt{x}-2\right)\left(\sqrt{x}+1\right)-\left(\sqrt{x}+2\right)\left(\sqrt{x}-1\right)}{\left(x-1\right)\left(\sqrt{x}+1\right)}\right)\frac{\left(x-1\right)^2}{2}\)
\(P=\left(\frac{\left(x-\sqrt{x}-2\right)-\left(x+\sqrt{x}-2\right)}{\left(x-1\right)\left(\sqrt{x}+1\right)}\right)\frac{\left(x-1\right)^2}{2}\)
\(P=\frac{2\sqrt{x}}{\left(x-1\right)\left(\sqrt{x}+1\right)}\frac{\left(x-1\right)^2}{2}\)
\(P=\frac{\sqrt{x}\left(x-1\right)}{\sqrt{x}+1}=\sqrt{x}\left(\sqrt{x}-1\right)=x-\sqrt{x}\)
Tìm x
\(\left(3x-\frac{1}{4}\right)\left(x+\frac{1}{2}\right)=0\)
Tìm X:
a) (0,5)x= (0,125)4
b) \(\left(\frac{3}{4}\right)^x=\frac{-81}{-256}\)
cho: A= [ 0,8.7+(0,8)^2] . (1,25.7 - 4/5 . 1,25) + 31,64,.
B=\(\frac{\text{(1,09-0,29) .5/4}}{\frac{\left(18,9-16,65\right).\frac{8}{9}}{ }}\)Hỏi A gấp mấy lần B
CMR:\(\sqrt{xy}\le\frac{|x|+|y|}{2}\left(xy>0\right)\)
18 : 3 x ( 1 + 2 ) = ? Mk làm là bằng 18 nhưng khi thấy ngta nói là biểu thức đó có thể viết ra được dưới dạng \(\frac{18}{3.\left(1+2\right)}=2\). Giải thích giúp mk với ?
\(\frac{2}{3}+\frac{4}{5}x\frac{5}{2}+\frac{1}{6}\)
Tìm x , biết :
a)\(x^3+5x^2+8x-4=0\)
b) \(\left(x^2+x\right)\left(x^2+x+1\right)=6\)