Question

 a, IxI = 3,5         b, Ix - 3I = \(\dfrac{1}{4}\)

c, Ix + \(\dfrac{1}{5}\)I            d, IxI = I\(-\dfrac{2}{3}\)I               e, I\(\dfrac{4}{5}\)xI = \(\dfrac{3}{10}\)  

giúp mik đi mik tích choa

Answer 1

`@ :|x| = 3,5`

`=> x = 3,5` hoặc `x = -3,5`

 

`@ : |x-3| = 1/4`

`TH1:`

`x-3=1/4`

`x=1/4+3`

`x=1/4+12/4`

`x=13/4`

Vậy `x=13/4`

`@TH2:`

`x-3=-1/4`

`x=-1/4+3`

`x=-1/4 + 12/4`

`x=11/4`

Vậy `x=11/4`

 

`@ : | x - 1/5|` thiếu đề ?

 

`@ : |x| = |-2/3|`

`=> |x| = 2/3`

`=>x = 2/3` hoặc `x =-2/3`

 

`@|4/5 x| = 3/10`

`@TH1:`

`4/5 x = 3/10`

`x=3/10 : 4/5`

`x=3/10 xx 5/4`

`x=3/8`

Vậy `x = 3/8`

`@TH2:`

`4/5 x = -3/10`

`x = (-3)/10 :4/5`

`x= (-3)/10 xx 5/4`

`x=(-3/8)`

Vậy `x = (-3)/8`

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