a)Với x>=0
\(\frac{5}{11}\sqrt{x}=\frac{1}{6}+\frac{1}{3}=\frac{1}{2}\)
\(\sqrt{x}=\frac{1}{2}:\frac{5}{11}=\frac{11}{10}\)
\(x=\frac{11^2}{10^2}=\frac{121}{100}\)(thỏa mãn)
b) x=0
c) \(x=\pm\sqrt{3}\)vì x<0 => \(x=-\sqrt{3}\)
d) x=1 hoặc -1
e) \(x=\pm\sqrt{2}\)
\(a,\frac{5}{11}\sqrt{x}-\frac{1}{3}=\frac{1}{6}.\)
\(\frac{5}{11}\sqrt{x}=\frac{1}{6}+\frac{1}{3}\)
\(\frac{5}{11}\sqrt{x}=\frac{1}{2}\)
\(\sqrt{x}=\frac{1}{2}:\frac{5}{11}\)
\(\sqrt{x}=\frac{11}{10}\)
\(\Rightarrow x=\frac{121}{100}\)
\(b.x^2=0\)
\(\Leftrightarrow x=0\)
\(c.x^2=3\left(x< 0\right)\)
\(\Leftrightarrow x=-\sqrt{3}\)
\(d.x^2=1\)
\(\Leftrightarrow\orbr{\begin{cases}x=1\\x=-1\end{cases}}\)
\(e.x^2=2\)
\(\Leftrightarrow x=\sqrt{2}\)
