mình viết nhầm=)))))
\(b,\frac{10}{99}\)+\(\frac{11}{199}\)+\(\frac{12}{299}\).\(\frac{1}{2}\)-\(\frac{1}{3}\)+\(\frac{-1}{6}\)
Các câu hỏi tương tự
\(\frac{4}{2.4}+\frac{4}{4.6}+\frac{4}{6.8}+...+\frac{4}{2012.2014}+\frac{4}{2014.2016}\)
Tính
giúp minh nha!!
Tính:
\(\frac{4}{2.4}+\frac{4}{4.6}+\frac{4}{6.8}+...+\frac{4}{2012.2014}+\frac{4}{2014.2016}\)
\(\frac{4}{2.4}\)\(+\frac{4}{4.6}\)\(+\frac{4}{6.8}\)\(+...+\frac{4}{2012.2014}\)\(+\frac{4}{2014.2016}\)
\(F=\frac{4}{2.4}+\frac{4}{4.6}+\frac{4}{6.8}+...+\frac{4}{2014.2016}\)
\(A=\frac{4}{2.4}+\frac{4}{4.6}+\frac{4}{6.8}+...+\frac{4}{2008.2010}\)
\(B=\frac{1}{18}+\frac{1}{54}+\frac{1}{108}+...+\frac{1}{990}\)
a\(\left(3-2\frac{1}{3}+\frac{1}{4}\right):\left(4-5\frac{1}{6}+2\frac{1}{4}\right)\)
b \(F=\frac{4}{2.4}+\frac{4}{4.6}+\frac{4}{6.8}+...+\frac{4}{2008.2010}\)
a,A=\(2\frac{1}{2}:\left(\frac{-1}{2}\right)^2-\frac{1}{-3}.\left(\frac{-1}{2}-\frac{4}{3}:\frac{-8}{9}\right)\)
b,B=\(\left(3\frac{10}{99}+4\frac{11}{99}-\frac{58}{299}\right).\left(\frac{1}{2}-\frac{4}{3}-\frac{1}{6}\right)\)
Tính :
a)\(\left[-\frac{1}{2}\right]^2:\frac{1}{4}-2\left[-\frac{1}{2}\right]^2\)
b)\(-\frac{7}{37}.1\frac{3}{8}-4\frac{5}{8}.\frac{7}{12}+\frac{1}{2}\)
c)\(F=\frac{1}{18}+\frac{1}{54}+\frac{1}{108}+...+\frac{1}{990}\)
d)\(H=\frac{4}{2.4}+\frac{4}{4.6}+\frac{4}{6.8}+...+\frac{4}{2018.2020}\)
Tính giá trị của biểu thức:
\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{2009.2010}\)
\(B=\frac{4}{2.4}+\frac{4}{4.6}+\frac{4}{6.8}+...+\frac{4}{2008.2010}\)
\(C=\frac{1}{18}+\frac{1}{54}+\frac{1}{108}+....+\frac{1}{990}\)