\(a,\frac{2}{3}+\frac{4}{5}=\frac{10}{15}+\frac{12}{15}=\frac{22}{15}\)
\(b,\frac{5}{12}+\frac{1}{6}=\frac{5}{12}+\frac{2}{12}=\frac{7}{12}\)
\(c,\frac{3}{4}+\frac{5}{6}=\frac{9}{12}+\frac{10}{12}=\frac{19}{12}\)
\(a\))\(\frac{2}{3}+\frac{4}{5}=\frac{10}{15}+\frac{12}{15}=\frac{22}{15}\)
b) \(\frac{5}{12}+\frac{1}{6}=\frac{5}{12}+\frac{2}{12}=\frac{7}{12}\)
c)\(\frac{3}{4}+\frac{5}{6}=\frac{9}{12}+\frac{10}{12}=\frac{19}{12}\)
2/3+4/5=10/15+12/15=22/15
5/12+1/6=5/12+2/12=7/12
3/4+5/6=9/12+10/12=19/12
quá dễ
a) 10/15 + 12/15 = 22/15
b) 5/12 + 2/12 = 7/12
c) 9/12 + 10/12 = 19/12
a)\(\frac{2}{3}+\frac{3}{4}=\frac{8+9}{12}=\frac{17}{12}\)
b) \(\frac{5}{12}+\frac{1}{6}=\frac{5+2}{12}=\frac{7}{12}\)
c) \(\frac{3}{4}+\frac{5}{6}=\frac{9+10}{12}=\frac{19}{12}\)
a)\(\frac{2}{3}\)+\(\frac{4}{5}\)=\(\frac{10}{15}\)+\(\frac{12}{15}\)=\(\frac{22}{15}\)
b)\(\frac{5}{12}\)+\(\frac{1}{6}\)=\(\frac{5}{12}\)+\(\frac{2}{12}\)=\(\frac{7}{12}\)
c)\(\frac{3}{4}\)+\(\frac{5}{6}\)=\(\frac{9}{12}\)+\(\frac{10}{12}\)=\(\frac{19}{12}\)