1.So sánh \(\frac{2016}{2017}+\frac{2017}{2018}\)với \(1\)( không tính kết quả )
2.So sánh: \(A=\frac{2015}{2016}+\frac{2016}{2017}+\frac{2017}{2018}\)và \(B=\frac{2015+2016+2017}{2016+2017+2018}\)
3. Với n là số nguyên dương hãy so sánh 2 phân số sau: \(\frac{n}{n+8}\)và \(\frac{n-2}{n+9}\)
So sánh A=\(\frac{2017^{2017}}{1+2017+2017^2+....+2017^{2016}}\)
B=\(\frac{2016^{2017}}{1+2016+2016^2+...+2016^{2016}}\)
\(\left(\frac{1}{2}+\frac{2015}{2016}+\frac{2016}{2017}+1\right)\left(\frac{2105}{2016}+\frac{2016}{2017}+\frac{7}{22}\right)-\left(\frac{1}{2}+\frac{2015}{2016}+\frac{2016}{2017}\right)\left(\frac{2015}{2016}+\frac{2016}{2017}+\frac{7}{22}+1\right)\)
So sánh A= \(\frac{2017^{2017}}{1+2017+2017^2+...+2017^{2016}}\)
B= \(\frac{2016^{2017}}{1+2016+2016^2+...+2016^{2016}}\)
SO SÁNH:
A = \(\frac{2017^{2017}}{1+2017+2017^2+...+2017^{2016}}\)
B = \(\frac{2016^{2017}}{1+2016+2016^2+...+2016^{2016}}\)
SO SÁNH A VÀ B:
A = \(\frac{2017^{2016}}{1+2017+2017^2+...+2017^{2016}}\)
B = \(\frac{2016^{2017}}{1+2016+2016^2+...+2016^{2016}}\)
so sanh A va B
\(A=\frac{2017^{100}}{1+2017+2017^2+2017^3+...+2017^{100}}\)
\(B=\frac{2016^{100}}{1+2016+2016^2+2016^3+...+2016^{100}}\)
so sánh A và B, biết:
A= \(\frac{2017^{2017}}{1+2017+2017^2+...+2017^{2016}}\) B= \(\frac{2016^{2017}}{1+2016+2016^2+...+2016^{2016}}\)
\(A=\frac{1}{2017}+\frac{2}{2017^2}+\frac{3}{2017^3}+...+\frac{2017}{2017^{2017}}+\frac{2018}{2017^{2018}}\). Chứng minh rằng : A < \(\frac{2017}{2016^2}\)