Các câu hỏi tương tự
\(A=\frac{101+100+99+98+....+3+2+1}{101-100+99-98+....+3-2+1}\)=?
Tính A =\(\frac{101+100+99+98+......+3+2+1}{101-100+99-98+......+3-2+1}\)
\(A=\frac{101+100+99+98+....+3+2+1}{101-100+99-98+...3-2+1}\) = ?
rút gọn :\(\frac{101+100+99+98+.,.+3+2+1}{101-100+99-98+...+3-2+1}\)
\(Tính:\frac{101+101+99+98+...+3+2+1}{101-100+99-98+...+3-2+1}\)
A=101+100+99+98+...+3+2+1/101-100+99-98+...+3-2+1
1 Tính
a) A=\(\frac{101+100+99+98+...+3+2+1}{101-100+99-98+...+3-2+1}\)
tính:
a) \(A=\frac{101+100+99+98+......+3+2+1}{101-100+99-98+........+3-2+1}\)
101+100+99+98+...+3+2+1/101-100+99-98+...+3-2+1