a)
\(\dfrac{1}{3}+\dfrac{2}{5}\left(x+1\right)=1\\ \Leftrightarrow\dfrac{2}{5}\left(x+1\right)=\dfrac{2}{3}\\ \Leftrightarrow x+1=\dfrac{5}{3}\\ \Rightarrow x=\dfrac{2}{3}\)
a) `1/3 + 2/5 (x+1)=1`
`2/5 (x+1) = 2/3`
`x+1=5/3`
`x=2/3`
b) `1/4 + 1/3 : 3x =-5`
`1/3 : 3x = -21/4`
`3x = -4/63`
`x=-4/189`
b) \(\dfrac{1}{4}+\dfrac{1}{3}:3x=-5\\ \Leftrightarrow\dfrac{1}{4}+\dfrac{1}{9}x=-5\\\Leftrightarrow\dfrac{1}{9}x=-\dfrac{21}{4}\\ \Rightarrow x=-\dfrac{189}{4} \)
Tìm \(x\)
a) \(\dfrac{1}{3}+\dfrac{2}{5}\left(x+1\right)=1\)
\(\dfrac{2}{5}\left(x+1\right)=1-\dfrac{1}{3}\)
\(\dfrac{2}{5}\left(x+1\right)=\dfrac{2}{3}\)
\(x+1=\dfrac{2}{3}\div\dfrac{2}{5}\)
\(x+1=\dfrac{5}{3}\)
\(x=\dfrac{5}{3}-1\)
\(x=\dfrac{2}{3}\)
Vậy \(x=\dfrac{2}{3}\).
b) \(\dfrac{1}{4}+\dfrac{1}{3}\div3x=-5\)
\(\dfrac{1}{4}+\dfrac{1}{9}x=-5\)
\(\dfrac{1}{9}x=-5-\dfrac{1}{4}\)
\(\dfrac{1}{9}x=-\dfrac{21}{4}\)
\(x=-\dfrac{21}{4}\div\dfrac{1}{9}\)
\(x=-\dfrac{189}{4}\)
Vậy \(x=-\dfrac{189}{4}\).
