\(10m+12n+15p=0\Rightarrow n=-\dfrac{10m+15p}{12}\)
Ta có:
\(\Delta=n^2-4mp=\left(-\dfrac{10m+15p}{12}\right)^2-4mp=\dfrac{100m^2-276mp+225p^2}{144}\)
\(=\dfrac{100}{144}\left(m-\dfrac{69}{50}p\right)^2+\dfrac{269}{600}p^2\ge0;\forall m;p\)
Nên pt đã cho luôn có nghiệm