Question

(a-b-c)^2-(a-b+c)^2

Answer 1

\(\left(a-b-c\right)^2-\left(a-b+c\right)^2\)

\(=\left(a-b-c-a+b-c\right)\left(a-b-c+a-b+c\right)\)

\(=-2c\cdot2\cdot\left(a-b\right)\)

\(=-4c\left(a-b\right)\)

Answer 2

\(\left(a-b-c\right)^2-\left(a-b+c\right)^2\\ =\left(a-b-c-a+b-c\right)\left(a-b-c+a-b+c\right)\\ =\left(-2c\right)\left(2a-2b\right)\\ =2\left(a-b\right)\left(-2c\right)\)