\(a,\dfrac{8}{2^n}=\dfrac{1}{32}\\ =>2^n=8\times32\\ =>2^n=256\\ =>2^n=2^8\\ =>n=8\\ -----------------\\ b,\dfrac{\left(-5\right)^n}{25}=-5\\ =>\left(-5\right)^n=25.\left(-5\right)\\ =>\left(-5\right)^n=-125\\ =>\left(-5\right)^n=\left(-5\right)^3\\ =>n=3\)