\(a,7\left(x-4\right)-3\left(x+8\right)=-84\)
\(7x-29-3x+24=-8\)
\(7x-3x=-8+29-24\)
\(4x=-3\Leftrightarrow x=-\frac{3}{4}\)
\(b,3\left(x-8\right)-6\left(x-5\right)=12\)
\(3x-24-6x-30=12\)
\(3x-6x=12+24+30\)
\(-3x=66\Leftrightarrow x=-22\)
\(c,3x-7⋮x-3\)
\(3\left(x-3\right)+2⋮x-3\)
Vì \(3\left(x-3\right)⋮x-3\)
\(\Rightarrow2⋮x-3\)
\(\Rightarrow x-3\inƯ\left(2\right)=\left\{\pm1;\pm2\right\}\)
Ta lập bảng
| x-3 | 1 | -1 | 2 | -2 |
| x | 4 | 2 | 5 | 1 |
a) 7.(x-4)-3.(x+8)=-84
7x-28-3x-24=-84
7x-3x=-84+28+24
4x=-32
x=-32:4
x=-9
Vậy x=-9
b) 3.(x-8)-6.(x-5)=12
3x-24-6x+30=12
3x-6x=12+24-30
-3x=6
x=6:(-3)
x=-2
Vậy x=-2
