a) 7/x = 3/12= 1/4
x = 28
b) \(x+x\cdot\frac{1}{4}:\frac{2}{7}+x:\frac{2}{9}=255\)
\(x+x\cdot\frac{7}{8}+x\cdot\frac{9}{2}=255\)
\(x.\left(1+\frac{7}{8}+\frac{9}{2}\right)=255\)
\(x\cdot\frac{51}{8}=255\Rightarrow x=40\)
a) \(\frac{7}{x}=\frac{3}{12}=>7.12=3.x=>x=\frac{7.12}{3}=28\)28
a) 7/x = 3/12
<=> x . 3 = 7 . 12
<=> x . 3 = 84
<=> x = 84 : 3
<=> x = 28
Vậy x = 28
\(a,\text{ }\frac{7}{x}=\frac{3}{12}=\frac{1}{4}=\frac{7}{28}\)
\(\Rightarrow\text{ }x=28\)
\(b,\text{ }x+x\text{ x }\frac{1}{4}\text{ : }\frac{2}{7}+x\text{ : }\frac{2}{9}=255\)
\(x+x\text{ x }\frac{7}{8}+x\text{ x }\frac{9}{2}=255\)
\(x\text{ x }\left(1+\frac{7}{8}+\frac{9}{2}\right)=255\)
\(x\text{ x }\frac{51}{8}=255\)
\(x=255\text{ : }\frac{51}{8}\)
\(x=40\)