đề bài là j vậy bn .vs cả số 3 và 2 là sao vậy?
Đúng 0
Bình luận (1)
Các câu hỏi tương tự
23 tháng 8 2023 lúc 20:33
5) (3-1/4+2/3) - (5-1/3-6/5) - (6-7/4+3/2) 6) (6-2/3+1/2) - (5+5/3-3/2)-(3-7/3+5/2)
7) (5/3-3/7+9)-(2+5/7-2/3)+(8/7-4/3-10) 8) (8-9/4+2/7)-(-6-3/7+5/4)-(3+2/4-9/7 pls help me
23 tháng 8 2023 lúc 20:58
(3-1/4+2/3) - (5-1/3-6/5) - (6-7/4+3/2) (6-2/3+1/2) - (5+5/3-3/2)-(3-7/3+5/2)
(5/3-3/7+9)-(2+5/7-2/3)+(8/7-4/3-10) (8-9/4+2/7)-(-6-3/7+5/4)-(3+2/4-9/7 )
mọi người ơi giúp mik với ạ
a)-1/24-[1/4-(1/2-7/8)]
b)(5/7-7/5)-[-1/2-(-2/7-1/10)
c)(-1/2)-(-3/5)+(-1/9)+1/71-(-2/7)+4/35-7/18
d) (3-1/4+2/3) -(5-1/3-6/5)-(6-7/4+3/2)
a)(5+1/5-2/9)-(2-1/23-3/35+5/6)-(8+2/7-1/18)
b) 1/3-3/4(-3/5+1/64- -2/9-1/36+1/15
c) -5/7-(-5/67)+13/10+1/2+(-1/6)+1 3/14-(-2/5)
d)3/5:(-1/15-1/6)+3/5:(-1/3-1 1/15)
tính A= 1/2 - 2/3 + 3/4 - 4/5 + 5/6 - 6/7 - 5/6 + 4/5 - 3/4 + 2/3 - 2/3 - 1/2
a = (7 +1/3-1/2) - (6-3/2 +5/3) - (-7/3+5+5/2)
Bài 1:
a) (6-2/3+1/2)-(5+5/3-2/3)-(3-7/3+5/2)
b)(-1/1/2:1,25)+(10/3/7:5/3/14)
c)(-2/3+1/7):121/42
A=(6-2/3+1/2)-(5+5/3-3/2)-(3-7/3+5/2)
A=(6-2/3+1/2)-(5+5/3-3/2)-(3-7/3+5/2) = ?