Question

a) -5(x^2 - 3x +1 ) + x ( 1+5x ) =x-2 

b) -4x (x-5) +7x (x-4) -3x^2 =12

Answer 1

`@` `\text {Ans}`

`\downarrow`

`a)`

\(-5(x^2 - 3x +1 ) + x ( 1+5x ) =x-2 \)

`=> -5x^2 + 15x - 5 + x + 5x^2 = x - 2`

`=> (-5x^2 + 5x^2) + (15x + x) - 5 = x - 2`

`=> 16x - 5 = x - 2`

`=> 16x - 5 - x + 2 = 0`

`=> (16x - x) + (-5+2) = 0`

`=> 15x - 3 = 0`

`=> 15x = 3`

`=> x = 3 \div 15`

`=> x =`\(\dfrac{1}{5}\)

Vậy, `x =`\(\dfrac{1}{5}\)

`b)`

\(-4x (x-5) +7x (x-4) -3x^2 =12\)

`=> -4x^2 + 20x + 7x^2 - 28x - 3x^2 = 12`

`=> (-4x^2 - 3x^2 + 7x^2) + (20x - 28x) = 12`

`=> -8x = 12`

`=> x = 12 \div (-8)`

`=> x = `\(-\dfrac{3}{2}\)

Vậy, `x =`\(-\dfrac{3}{2}\)

`@` `\text {Kaizuu lv uu}`