\(\left(5x-1\right)\left(\frac{2x-1}{3}\right)=0\)
\(\Leftrightarrow\left(\frac{\left(5x-1\right)\left(2x-1\right)}{3}\right)=0\)
\(\Leftrightarrow\left(5x-1\right)\left(2x-1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}5x-1=0\\2x-1=0\end{cases}}\)\(\Rightarrow\orbr{\begin{cases}x=\frac{1}{5}\\x=\frac{1}{2}\end{cases}}\)
Vậy \(x=\frac{1}{5}\)hoặc\(x=\frac{1}{2}\)
b) \(\left(-0,6x-\frac{1}{2}\right).\frac{3}{4}-\left(-1\right)=\frac{1}{3}\)
\(\Leftrightarrow\left(-0,6x-\frac{1}{2}\right).\frac{3}{4}=\frac{-2}{3}\)
\(\Leftrightarrow\left(-0,6x-\frac{1}{2}\right)=\frac{-8}{9}\)
\(\Leftrightarrow-0,6x=\frac{-7}{18}\)
\(\Rightarrow x=\frac{35}{54}\)
ý a) \(\left(5x-1\right)\left(\frac{2x-1}{3}\right)=0\)
\(\Leftrightarrow\left(5x-1\right)\left(2x-1\right)=0\)
=> x=\(\frac{1}{5}\)hoặc x=\(\frac{1}{2}\)
c)\(\left(4x-9\right)\left(2,5+\frac{-7}{3}x\right)=0\)
\(\Rightarrow4x-9=0\) hoặc \(\frac{5}{2}+\frac{-7}{3}x=0\)
\(\Rightarrow x=\frac{9}{4}\)hoặc \(x=\frac{15}{14}\)
cho mk hỏi ý d (3/8x+?) với bao nhiêu vậy