Question

a) \(5\dfrac{6}{7}+3\dfrac{5}{8}=\)

b)\(10\dfrac{7}{10}-4\dfrac{3}{10}=\)

Answer 1

\(a,5\dfrac{6}{7}+3\dfrac{5}{8}=\dfrac{41}{7}+\dfrac{29}{8}=\dfrac{531}{56}\)

\(b,10\dfrac{7}{10}-4\dfrac{3}{10}=\dfrac{107}{10}-\dfrac{43}{10}=\dfrac{64}{10}=\dfrac{32}{5}\)

Answer 2

5\(\dfrac{6}{7}\) + 3\(\dfrac{5}{8}\) \(=\dfrac{41}{7}+\dfrac{29}{8}=\dfrac{328+203}{56}=\dfrac{531}{56}\)

\(10\dfrac{7}{10}-4\dfrac{3}{10}=\dfrac{107}{10}-\dfrac{43}{10}=\dfrac{64}{10}\)

Answer 3

\(a.5\dfrac{6}{7}+3\dfrac{5}{8}=\dfrac{41}{7}+\dfrac{29}{8}=\dfrac{328}{56}+\dfrac{203}{56}=\)\(\dfrac{531}{56}\)

\(b.10\dfrac{7}{10}-4\dfrac{3}{10}=\dfrac{107}{10}-\dfrac{43}{10}=\dfrac{32}{5}\)