a) \(\dfrac{5}{6}+\dfrac{3}{2} . \dfrac{4}{5}=\dfrac{5}{6}+\dfrac{3 . 4}{2 . 5}=\dfrac{5}{6}+\dfrac{6}{5}=\dfrac{61}{30}\)
b)\(\dfrac{6}{7} : \dfrac{9}{14}-1=\dfrac{6}{7} . \dfrac{14}{9}-1=\dfrac{4}{3}-1=\dfrac{4}{3}-\dfrac{3}{3}=\dfrac{1}{3}\)
a)\(=\dfrac{61}{30}\)
b)\(=\dfrac{1}{3}\)