a, 520+(218-x)=720
=> 218-x=200
=> x=18
Vậy x=18
b, x30 =x
=> x30-x=0
=>x(x29-1)=0
\(\Rightarrow\hept{\begin{cases}x=0\\x^{29}-1=0\end{cases}\Rightarrow\hept{\begin{cases}x=0\\x^{29}=1\end{cases}}}\)\(\Rightarrow\hept{\begin{cases}x=0\\x=1\end{cases}}\)
Vậy x=0 hoặc x=1
a) 520 + (218 - x) = 720
218 - x = 720 - 520
218 - x = 200
x = 218 - 200
x = 18
Đúng tk cho mk nha
a) 520+(218-x)=720
-> 218-x=200
->x=18
~Hok tốt~
a/ \(520+\left(218-x\right)=720\)
\(218-x=720-520\)
\(218-x=200\)
\(x=218-200\)
\(x=18\)
Vậy \(x=18\)
b/ \(x^{30}=x\)
\(x^{30}-x=0\)
\(x\times\left(x^{29}-1\right)=0\)
\(\Rightarrow[\frac{x=0}{x^{29}-1=0}\Rightarrow[\frac{x=0}{x^{29}=1}\Rightarrow[\frac{x=0}{x=1}\)
\(\Rightarrow x=\left\{0;1\right\}\)
Vậy \(x=\left\{0;1\right\}\)
a) 520+(218-x)=720
-> 218-x=200
->x=18
~Hok tốt~
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