Question

a) 3x.(x+1) - 2x.(x+ 2) = -1 - x

Answer 1

\(3x\left(x+1\right)-2x\left(x+2\right)=-1-x\)

\(3x^2+3x-2x^2-4x+1+x=0\)

\(3x^2-2x^2+3x-4x+x+1=0\)

\(x^2+1=0\\ x^2=-1\left(voli\right)\)

Answer 2

3x(x+1) - 2x(x+2) = -1 - x
3x(x+1) - 2x(x+2) + 1 - x =0
3x\(^2\) + 3x - 2x\(^2\) - 4x + 1 - x =0
x\(^2\) - 2x + 1=0
(x - 1)\(^2\) = 0
x - 1 =0
     x=1