TA CÓ: 3/x+2 =5/ 2x+1
=> 3/x+2 - 5/2x+1 = 0
=>3(2x+1) - 5(x+2)/ (x+2)(2x+1) =0
=> 6x + 3 - 5x - 10/ (x+2)(2x+1) =0
=> x-7/ (x+2)(2x+1) =0
mà (x+2)(2x+1) khác không nên x-7 = 0
=> x=7
b) Ta có : -8/3x -1 =4/-7
=>-8/3x-1 = 8/-14= -8/14
=>3x-1 = 14
=> 3x =14+1 =15
=> x = 15/3 =5
\(\frac{3}{x}+2=\frac{5}{2}+1\)
\(\frac{3}{x}+2=\frac{7}{2}\)
\(\frac{3}{x}=\frac{7}{2}-2\)
\(\frac{3}{x}=\frac{3}{2}\)
Suy ra x = 2
chúc bạn học tốt!
Ta có: \(\frac{3}{x+2}=\frac{5}{2x+1}\)
\(\Leftrightarrow3.\left(2x+1\right)=5.\left(x+2\right)\)
\(\Rightarrow6x+3=5x+10\)
\(\Rightarrow6x-5x=10-3\)
\(\Rightarrow x=7\)