\(a)3^{x+1}-3^x=162\)
\(\Leftrightarrow3^x\cdot3-3^x=162\)
\(\Leftrightarrow3^x\left(3-1\right)=162\)
\(\Leftrightarrow3x\cdot2=162\)
\(\Leftrightarrow3x=162:2\)
\(\Leftrightarrow3x=81\)
\(\Leftrightarrow x=81:3\)
\(\Leftrightarrow x=27\)
Vậy x=27
\(b)\left(1-x\right)^3=216\)
\(\Leftrightarrow\left(1-x\right)^3=6^3\)
\(\Leftrightarrow x-1=6\)
\(\Leftrightarrow x=6+1\)
\(\Leftrightarrow x=7\)
Vậy x=7
\(c)5^{x+1}-2\cdot5^x=375\)
\(\Leftrightarrow5^x\cdot5-2\cdot5^x=375\)
\(\Leftrightarrow5^x\cdot\left(5-2\right)=375\)
\(\Leftrightarrow5^x\cdot3=375\)
\(\Leftrightarrow5^x=375:3\)
\(\Leftrightarrow5^x=125\)
\(\Leftrightarrow5^x=5^3\)
\(\Leftrightarrow x=3\)
Vậy x=3
