Question

`a) ( 3x - 6) . 3 = 3^4`

`b) 12x - 33 = 3^2 . 3^3`

Answer 1

\(a.3x-6=\dfrac{3^{^4}}{3}=3^{^3}\\ 3x=27+6=33\\ x=\dfrac{33}{3}=11\\ b.12x-33=3^{^2}\cdot3^{^3}\\ 12x=3^{^5}+33=276\\ x=\dfrac{276}{12}=23\)

Answer 2

`a) ( 3x - 6) . 3 = 3^4`

`=> ( 3x - 6 ) . 3^1 = 3^4`

`=> 3x -6 = 3^4  : 3^1`

`=> 3x - 6 = 3^3`

`=> 3x - 6 = 27`

`=> 3x = 27 + 6`

`=> 3x = 33`

`=> x = 11`

`b) 12x - 33 = 3^3 . 3^3`

`=> 12x - 33 = 3^(2+3)`

`=> 12x - 33 = 3^5`

`=> 12x - 33 = 243`

`=> 12x = 243 + 33`

`=> 12x = 276`

`=> x = 23`

Answer 3

Lời giải:

a.

$(3x-6).3=3^4$

$3x-6=3^4:3=27$

$3x=27+6=33$

$x=33:3=11$

b. 

$12x-33=3^2.3^3=3^5=243$

$12x=243+33=276$

$x=276:12=23$