a) (3x - 2)5 = -243
=> (3x - 2)5 = (-3)5
=> 3x - 2 = -3
=> 3x = -3 + 2 = -1
=> x = -1/3
b) 2x - 32 = 16
=> 2x = 16 + 32 = 16 + 9 = 25
=> x = 25/2
a, (2x-3)2=16
b, (3x-2)5=-243
c, (x-7)x+1=(x-7)x+11
tìm x a) (2x - 32)=16 b) (3x - 2)= -243
Tìm x€Q
a)2^x=16
b)3^x+1=9^x
c)2^3x+2=5^x+2
d)3^2x-1=243
tìm x thuộc Q biết:
a) (2x-3)2 =16
b) ( 3x-2)5=243
c) (7x+2)-1=52
d) ( x-3/4)4=81
bài 1 . Tìm x , biết
a) a.2x=16
b) 3 x+1 =9x
c) 23x+2=4x+5
d) 32x-1 =243
Tìm x, biết rằng: a) 2x = 16 b) 3x+1 = 9xc) 23x+2 = 4x+5d) 32x-1 = 243
tìm x :
a) 3x-3^2=25
b)2x-3^5=-243
c)5x+2^-1=3^-2
Tìm \(x\in Q\),biết :
a) \(\left(2x-3\right)^2=16\)
b) \(\left(3x-2\right)^5=-243\)
c) \(\left(7x+2\right)^{-1}=3^{-2}\)
\(\text{a) 3^{2x} * 9^{2x}=3^{12} b) 7^{3x}= 7^5}:7^3c25x^2=25d\left(x-\frac{\left(2\right)}{3}\right)^5=\frac{1}{243}\)
