a) \(3+\dfrac{5}{2}=\dfrac{6}{2}+\dfrac{5}{2}=\dfrac{11}{2}\)
b) \(\dfrac{2}{8}:\dfrac{4}{8}=\dfrac{2}{8}.\dfrac{8}{4}=\dfrac{2}{4}=\dfrac{1}{2}\)
c) \(\dfrac{13}{5}-2=\dfrac{26}{10}-\dfrac{20}{10}=\dfrac{6}{10}=\dfrac{3}{5}\)
a)\(=\dfrac{6}{2}+\dfrac{5}{2}=\dfrac{11}{2}\)
b)\(=\dfrac{2}{8}\cdot\dfrac{8}{4}=\dfrac{2}{4}=\dfrac{1}{2}\)
c)\(=\dfrac{13}{5}-\dfrac{10}{5}=\dfrac{3}{5}\)
a \(\dfrac{18}{6}+\dfrac{15}{6}=\dfrac{33}{6}=\dfrac{11}{2}\)
b \(\dfrac{2}{8}\times\dfrac{8}{4}=\dfrac{2}{1}\times\dfrac{1}{4}=\dfrac{2}{4}=\dfrac{1}{2}\)
c \(\dfrac{13}{5}-\dfrac{10}{5}=\dfrac{3}{5}\)
a,\(3+\dfrac{5}{2}=\dfrac{6}{2}+\dfrac{5}{2}=\dfrac{11}{2}\)
b,\(\dfrac{2}{8}:\dfrac{4}{8}=\dfrac{2}{8}x\dfrac{8}{4}=\dfrac{16}{32}=\dfrac{1}{2}\)
c,\(\dfrac{13}{5}-2=\dfrac{13}{5}-\dfrac{10}{5}=\dfrac{3}{5}\)