Question

a) 3\(\dfrac{1}{4}\) + 5\(\dfrac{5}{12}\)=?

b) 7 - 4\(\dfrac{1}{3}\) =?

c) \(\dfrac{15}{9}x3\dfrac{2}{7}=?\)

d) 7 : 9\(\dfrac{1}{3}=?\)

 

Answer 1

\(a,3\dfrac{1}{4}+5\dfrac{5}{12}=\dfrac{13}{4}+\dfrac{65}{12}=\dfrac{39}{12}+\dfrac{65}{12}=\dfrac{104}{12}=\dfrac{26}{3}\)

\(b,7-4\dfrac{1}{3}=\dfrac{7}{1}-\dfrac{13}{3}=\dfrac{21}{3}-\dfrac{13}{3}=\dfrac{8}{3}\)

\(c,\dfrac{15}{9}.3\dfrac{2}{7}=\dfrac{15}{9}.\dfrac{23}{7}=\dfrac{345}{63}=\dfrac{115}{21}\)

\(d,7:9\dfrac{1}{3}=\dfrac{7}{1}:\dfrac{28}{3}=\dfrac{7}{1}.\dfrac{3}{28}=\dfrac{21}{28}=\dfrac{3}{4}\)