Question

a) 3^6÷3^2+2^3×2^2

b) (2100-63)÷21

c) 32×59+41×32

d) 99-97+95-93+91+89+...+9-5+3-1

 

 

Answer 1

a) 3 ^ 6 : 3 ^ 2 + 2 ^ 3 + 2 ^ 2 

 = 3^{6 - 2}  + 2^{3 + 2} 

  = 3⁴ + 2⁵  = 81 + 32 

  = 113 .

b) ( 2100 - 63 ) : 21

 = 2037 : 21

 = 97 .

c) 32 x 59 + 41 x 32

 = 32 x ( 59 + 41 )

 = 32 x 100

 = 3200 .

d) 99 - 97 + 95 - 93 + 91 - 89 + ... + 7 - 5 + 3 - 1 ( 50 so = 25 hieu )

= 2 + 2 + 2 + ... + 2 + 2 = 2 x 25 

= 50 .

Answer 2

a)   \(3^6:3^2+2^3.2^2=3^4+2^5=113\)

b)   \(\left(2100-63\right):21=2037:21=97\)

c)    \(32.59+41.32=32.\left(59+41\right)=32.100=3200\)

d)   \(99-97+95-93+........+9-7+5-3+1=2+2+...+2+1=25.2+1=50+1=51\)

Answer 3

giải giúp mik bài này nha

12x-33=3^2.3^3

Answer 4

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