a)\(35.43+35.56+35\)
\(=35.\left(43+56+1\right)\)
\(=35.100\)
\(=3500\)
b)\(37.24+37.76+63.79+21.63\)
\(=37.\left(24+76\right)+63.\left(79+21\right)\)
\(=37.100+63.100\)
\(=100.\left(37+63\right)\)
\(=100.100\)
\(=10000\)
\(a,35.43+35.56+35=35.\left(43+56+1\right)=35.100=3500\)
\(b,37.24+37.76+63.7+21.63=37.\left(24+76\right)+63.\left(79+21\right)=37.100+63.100\)
\(=100.\left(37+63\right)=100.100=10000\)
\(c,1213-\left[1250-\left(4^2-2.3\right)^3:4\right]-\left|3\right|=1213-\left[1250-\left(16-6\right)^3:4\right]-3\)
\(=1213-\left[1250-10^3:4\right]-3=1213-\left[1250-250\right]-3\)
\(=1213-1000-3=213-3=210\)
\(d,\left(2^{17}+15^3\right).\left(3^{45}-6^5\right).\left(2^4-4^2\right)=\left(2^{17}+15^3\right).\left(3^{45}-6^5\right).\left[4^4-\left(2.2\right)^2\right]\)
\(=\left(2^{17}+15^3\right).\left(3^{45}-6^5\right).\left[2^4-2^2.2^2\right]=\left(2^{17}+15^3\right).\left(3^{45}-6^5\right).0=0\)