`@` `\text {Ans}`
`\downarrow`
`a,`
\(\dfrac{3}{2}\times\dfrac{4}{5}-x=\dfrac{2}{3}\)
\(\dfrac{6}{5}-x=\dfrac{2}{3}\)
\(x=\dfrac{6}{5}-\dfrac{2}{3}\)
\(x=\dfrac{8}{15}\)
Vậy, `x = \dfrac{8}{15}`
`b,`
\(x\times3\dfrac{1}{3}=3\dfrac{1}{3}\div4\dfrac{1}{4}\)
\(x\times3\dfrac{1}{3}=\dfrac{40}{51}\)
\(x=\dfrac{40}{51}\div3\dfrac{1}{3}\)
\(x=\dfrac{4}{17}\)
Vậy, `x=`\(\dfrac{4}{17}\)
`c,`
\(5\dfrac{2}{3}\div x=3\dfrac{2}{3}-2\dfrac{1}{2}\)
\(\dfrac{17}{3}\div x=\dfrac{7}{6}\)
\(x=\dfrac{17}{3}\div\dfrac{7}{6}\)
\(x=\dfrac{34}{7}\)
Vậy, `x=`\(\dfrac{34}{7}\)
a,\(\dfrac{3}{2}.\dfrac{4}{5}-x=\dfrac{2}{3}\)
\(\dfrac{4}{5}-x=\dfrac{2}{3}:\dfrac{3}{2}\)
\(\dfrac{4}{5}-x=\dfrac{4}{9}\)
\(x=\dfrac{4}{5}-\dfrac{4}{9}\)
\(x=\dfrac{16}{45}\)
b,\(x.3.\dfrac{1}{3}=\dfrac{31}{3}\div\dfrac{4}{14}\)
\(x.3.\dfrac{1}{3}=\dfrac{217}{6}\)
\(x.3=\dfrac{217}{6}\div\dfrac{1}{3}\)
\(x\div3=\dfrac{217}{2}\)
\(x=\dfrac{217}{2}\div3\)
\(x=\dfrac{217}{6}\)
c, \(\dfrac{52}{3}:x=\dfrac{32}{3}-\dfrac{21}{2}\)
\(\dfrac{52}{3}:x=\dfrac{1}{6}\)
\(x=\dfrac{52}{3}:\dfrac{1}{6}\)
\(x=104\)
a) 16/45
b) 217/6
c) 34/7