=> A = 3(1 + 3 + 32) + 34(1 + 3 + 32) + ..... + 328(1 + 3 + 32)
=> A = 3.13 + 34.13 + ..... + 328.13
=> A = 13( 3 + 34 + ..... + 328) chia hết cho 13
Ta có : A = 3 + 32 + 33 + ..... + 329 + 330
=> A = (3 + 32 + 33) + (34 + 35 + 36) + ...... + (328 + 329 + 330)
=> A = 3(1 + 3 + 32) + 34(1 + 3 + 32) + ..... + 328(1 + 3 + 32)
=> A = 3.13 + 34.13 + ..... + 328.13
=> A = 13( 3 + 34 + ..... + 328) chia hết cho 13
\(A=3+3^2+3^3+3^4+...+3^{29}+3^{30}\)
\(A=\left(3+3^2+3^3\right)+\left(3^4+3^5+3^6\right)+...+\left(3^{28}+3^{29}+3^{30}\right)\)
\(A=3\times\left(1+3+3^2\right)+3^4\times\left(1+3+3^2\right)+...+3^{28}\left(1+3+3^2\right)\)
\(A=\left(1+3+3^2\right)\times\left(3+3^4+...+3^{28}\right)\)
\(A=13\times\left(3+3^4...+3^{28}\right)\)
Có : \(13\times\left(3+3^4+...+3^{28}\right)⋮13\)
\(\Rightarrow A⋮13\)
Ta có : A = 3 + 32 + 33 + ..... + 329 + 330
=> A = (3 + 32 + 33) + (34 + 35 + 36) + ...... + (328 + 329 + 330)
=> A = 3(1 + 3 + 32) + 34(1 + 3 + 32) + ..... + 328(1 + 3 + 32)
=> A = 3.13 + 34.13 + ..... + 328.13
=> A = 13( 3 + 34 + ..... + 328) chia hết cho 13