\(2x\left(x-\frac{2}{3}\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}2x=0\\x-\frac{2}{3}=0\end{cases}\Leftrightarrow\orbr{\begin{cases}x=0\\x=\frac{2}{3}\end{cases}}}\)
Vậy x = 2 hoặc x = 2/3
\(\frac{37-x}{x+13}=\frac{3}{7}\)
\(\Rightarrow\left(37-x\right)\times7=\left(x+13\right)\times3\)
\(\Rightarrow259-7x=3x+39\)
\(-7x-3x=39-259\)
\(-10x=-220\)
\(x=22\)