Các câu hỏi tương tự
tìm x biết:
(3x-1) [- 1/2x+5]=0
1/4+1/3:(2x-1)=-5
[2x+3/5]2 - 9/25=0
-5(x+1/5)-1/2(x-2/3)=3/2x - 5 /6
[x+1/2]x [2/3-2x]=0
17/2-|2x-3/4|=-7/4
2/3x-1/2x =5/12
(x+1/5)2+17/25=26/25
[x.44/7+3/7].11/5-3/7=-2
3[3x-1/2]+1/9=0
Tìm x biết:
a) (2x + 3/5)^2 - 9/25 = 0
b) 3.(3x - 1/2)^3 +1/9 =0
(2x+3/5)^2-9/25=0
3(3x-1)^3+1/9=0
nêu cách làm
- Tìm x
2 . ( x - 1/2 ) ^ 3 - 1/4 = 0
( 3x -1 ) ( - 1/2x + 5 ) = 0
( 2n + 3/5 ) ^ 2 - 9/25 = 0
3 ( 3n - 1/2 ) ^ 3 + 1/9 = 0
Tìm x biết:
a,(2x+3/5)^2-9/25=0
b,(3x-1).(-1/2x+5)=0
c, (7/5)^x+1-(1/5)^x=-4/625
d,(2/3)^x+2+(2/3)^x+1=20/27
Bài 1: Tìm x, biết:
a, (2x + 3/5)2 = \(\frac{9}{25}\)
b, 3(3x-1/2)3+1/9=0
c, -5(x+1/5)-1/2(x-2/3)=2/3x-5/6
d, 3(x-1/2)-5(x+3/5)=x+1/5
3/4-2 I 2x-2/3 I
(3x-1) (-1/2 x+5)=0
- 2/3 x-1/2x=5/12 chi tiết nha các bạn
(2x+3/5)^2-9/25=0
3 (3x -1/2) 3+1/9=0
Bài 1:a)-2x-3.( x-17 ) 34-2.( -x+25 )b)17x+3.( -16x-37 ) 2x+43-4xc){-3x+2. [ 45-x-3 ( 3x+7 ) -2x]+4x} 55g)-103-57: [ 5.( 2x-1 )2-( -9 )0 ]Bài 2:a)-5.( -x+7 )-3.( -x-5 )-4.( 12-x )+48b)7.( -x-7 )-4.( -2x-11 )7.( 4x+10 )+9c)-2.( 15-3x )-4.( -7x+8 )-5-9.( -2x+1 )d)5.( -3x-7 )-4.( -2x-11 )7.( 4x+10 )+9e)4( x-2 )2-13( -3 )2.2-11.( -3 )f)-52-( 2x-1 )3( -13 ).( -3 )
Đọc tiếp
Bài 1:
a)-2x-3.( x-17 )= 34-2.( -x+25 )
b)17x+3.( -16x-37 )= 2x+43-4x
c){-3x+2. [ 45-x-3 ( 3x+7 ) -2x]+4x} = 55
g)-103-57: [ 5.( 2x-1 )2-( -9 )0 ]
Bài 2:
a)-5.( -x+7 )-3.( -x-5 )=-4.( 12-x )+48
b)7.( -x-7 )-4.( -2x-11 )=7.( 4x+10 )+9
c)-2.( 15-3x )-4.( -7x+8 )=-5-9.( -2x+1 )
d)5.( -3x-7 )-4.( -2x-11 )=7.( 4x+10 )+9
e)4( x-2 )2-13=( -3 )2.2-11.( -3 )
f)-52-( 2x-1 )3=( -13 ).( -3 )
\(\left(3x-1\right).\left(\frac{-1}{2}x+5\right)=0\)
\(\frac{1}{4}+\frac{1}{3}:\left(2x-1\right)=-5\)
\(\left(2x+\frac{3}{5}\right)^{^2}-\frac{9}{25}=0\)
\(3\left(3x-\frac{1}{2}\right)+\frac{1}{9}=0\)